Error: Subscripted assignment dimension mismatch

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A 2011년 8월 30일

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https://kr.mathworks.com/matlabcentral/answers/14789-error-subscripted-assignment-dimension-mismatch

채택된 답변: Fangjun Jiang

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Hello,

I have a 48x64 matrix, let's call it dummy, and I have located all of the non-zero values in dummy(:).

returned as num:

num=find(dummy);

num=

then I want to find the actual value contained at these positions in dummy(:)

values=zeros(size(num));

for i=1:length(num)

values(i,1)=dummy(num(i));

end

values=sort(values);

values=

I now need to find the values in the original 48x64 dummy matrix which are equal to these values.

Right now, I am using:

points=zeros(length(num),2);

for i=1:length(values)

[points(i,1),points(i,2)]=find(z(:,:,pos)==values(i));

end

HOWEVER, occasionally there are repeated values, and therefore more than one [x,y] coordinate found

When this occurs, I get the error "Subscripted assignment dimension mismatch."

I have been struggling with this for some time, as it appears I cannot do:

x=find(z(:,:,pos)==values(i));

[points(i,1),points(i,2)]=X(1,1);

This error is " Indexing cannot yield multiple results."

As well, this is not ideal because I would like to have the coordinates from all values; if the above were to work it would only give me the coordinates for the first of the repeated values.

Any input is greatly appreciate, thank you in advance for your replies!