Substitute blank entries in a cell array by elements from a double matrix

I have a cell type variable A with 500 rows and 3 columns:

     c1   y     v       c1      c2      c3
  A={13    1999  47,7  13  183  []  []  0
     141  1999  60,2  141  308  []  []  0
     174  1999  51,9  174  308  []  []  0
     181  1999  52,9  181  183  []  []  0}

And I have a double variable B with 2000 rows and 3 columns:

    y           c1      c3 
 B=[1999  13  32
    1999  67  189
    1999  140  40
    1999  141  55
    1999  143  53
    1999  174  38
    1999  177  63
    1999  181  30
    1999  185  51]

If the first column of A matches the second column of B (if the c1s match in A and B) then I would like to substitute the blank entries [ ] in the sixth column of A (c3) by the values of the third column of B (c3). So my new A:

A={13  1999  47,7  13  183  32  []  0
   141  1999  60,2  141  308  55  []  0
   174  1999  51,9  174  308  38  []  0
   181  1999  52,9  181  183  30  []  0}

Thank you

Answer 1

[Azzi Abdelmalek]

A={13    1999  47.7  13  183  []  []  0
   141  1999  60.2  141  308  []  []  0
   174  1999  51.9  174  308  []  []  0
   181  1999  52.9  181  183  []  []  0}
B=[1999  13  32
  1999  67  189
  1999  140  40
  1999  141  55
  1999  143  53
  1999  174  38
  1999  177  63
  1999  181  30
  1999  185  51]
[ii,jj]=ismember(B(:,2),[A{:,1}]')
A(nonzeros(jj),6)=num2cell(B(ii,3))

Answer 2

[Andrei Bobrov]

c = cell2mat(A(:,4));
A(:,6) = num2cell(B(ismember(B(:,2),c),3));