Large binned matrix reshape

I was trying to find a similar solution to my problem, but I couldn't find any exact solution. I have a large matrix of 2000x100, similar data is binned in to 10 different matrices. Each of the bins are 2000x10.

That matrix is right now, bin1(2000x10) bin2 (2000x10) ......... bin10(2000x10).

I am trying to reshape the such a way that it will be ,

bin1 (2000x10)

bin2 (2000x10)

.

.

.

bin10. (2000x10)

So I should be ending up with a dataset of 20000x10. The bins need to be converted in the same sequence.

Answer 1

[Matt J]

tmp=num2cell(reshape(yourMatrix,200,10,10),[1,2]);

result=vertcat(tmp{:});

[Avik Mahata]

Thanks Matt for taking time to reply. This trick worked. Thanks a lot. Wish you a happy long weekend.

[Image Analyst]

Not sure why going to a cell array, tmp, was necessary. Since you said your "data is binned in to 10 different matrices" of size 2000 x 100 (which is not large by the way) then why can't you simply combine your 10 different matrices like this:

% Vertically stack the "10 different matrices" that the user has:
allBins = vertcat(bin1, bin2, bin3, bin4, bin5, bin6, bin7, bin8, bin9, bin10);

as I suggested in my answer? Why convert each matrix into a cell array?

Answer 2

[Image Analyst]

Wouldn't it just be

% Vertically stack the "10 different matrices" that the user has:
allBins = vertcat(bin1, bin2, bin3, bin4, bin5, bin6, bin7, bin8, bin9, bin10);

??? Or is that not the ordering you wanted?