Hi!
I'd like to obtain the result in the output according to the variables A1, A2, A3 and values.
A1 = [100; 130; 160; 2100]
A2 = [200; 10; 150; 230]
A3 = [300; 120; 1400; 220]
Values = [100; 1400; 200; 150; 1400]
output = [A1; A3; A2; A2; A3]
Please, how can I achieve this? May someone help me?

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John D'Errico
John D'Errico 2021년 9월 30일
편집: John D'Errico 2021년 9월 30일
How are the input and output related?
While I might make a wild guess that a sort is somehow important here, there are THREE vectors A1,A2,A3, but there are 4 diatinct values in the vector Values. So how should we guess to do what here?
The crystal ball is just so foggy today.
Thanks for you reply.
I'll try to explain.
The vector A1, A2 and A3 are 4 fix values.
The vector " Values" show numbers which are found in the vectors A1, A2 and A3.
I'd like to find which vector A1, A2 or A3 each number in the Value vector repeats?
For example:
Values = [ 130; 1400; 230]
The answer will be:
output = [ A1; A3; A2]

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DGM
DGM 2021년 9월 30일
We're going down a bad road if we're trying to use variable names as variables. If instead of using numbered variables, A1,A2,A3, etc were column vectors of an array:
A1 = [100; 130; 160; 2100];
A2 = [200; 10; 150; 230];
A3 = [300; 120; 1400; 220];
A = [A1 A2 A3];
Values = [100; 1400; 200; 150; 1400; 4]; % what if numbers aren't in A?
[~,idx] = ismember(Values,A);
idx(idx==0) = NaN; % ignore values which are not members of A
[~,col] = ind2sub(size(A),idx)
col = 6×1
1 3 2 2 3 NaN
The result is the column subscript describing where the number is. This makes the output usable, as A can simply be indexed by subsequent code. A vector of variable names is not useful for anything but creating more problems.
If A1, etc are not the same length, similar can be done with a cell array and some modification.

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Many Thanks!! It works for my problem. Thanks for your explanation!

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