Hi all,
Assuming that I have the follwing data:
x=[0, 2, 2.4, 2.8, 3.4, 3.9, 4, 4,7, 5.3, 5.8, 6, 6.4......]; % unit of x is cm
y=[100, 50, 30, 25, 20, 16, 14, 13, 12, 11, 10.5, 10, ....]; % Intensity
My question is the following:
I can plot y vs. x but I Would like, for instance, to bin x with a constant bin width (constant distance). Let say bin width of 2 (constant distance 2 cm). Therefore I would like to obtain a new x called xn:
xn=[0, 2, 4, 6,..]
and yn should contain the sum of the data which are conatained in in each interval:
interval1=[0,2] contains 100+50=150
interval2=]2,4] contains 50 + 30 + 25 + 20 + 16 + 14 =155
interval3=]4,6] contains 56.5
yn=[150, 155, 56.5]
and then I would like to plot yn versu xn
your hepl is highly welcome....
cheers

답변 (1개)

the cyclist
the cyclist 2014년 8월 5일

0 개 추천

You should be able to do this with the hist() or histc() command. You can specify your bin locations, and then get the index for which x values went into each bin. Then use that index to sum your y values.

댓글 수: 5

Adam
Adam 2014년 8월 5일
Hi ,
Thanks for your quick reply: I did it in the following way:
[n,bin] = histc(x,linspace(min(x),max(x),200)); yn=full(mean(sparse(1:length(x),bin,y)))
but this gives the mean and not the sum. xn now is xn=1:200 ? ist correct?
cheers
the cyclist
the cyclist 2014년 8월 5일
The first part is basically right, but I'm not quite sure what you're doing in the definition of yn. I would do this:
% Same as your code, but I explicitly define the bin edges as a variable
binEdge = linspace(min(x),max(x),200);
[n,bin] = histc(x,binEdge);
% Sum up the values in each bin.
yn = accumarray(bin',y);
% Plot
figure
plot(binEdge,yn)
The accumarray function is a powerful one. It is effectively looping through all of the bin numbers in the bin variable, and summing the corresponding values of y.
I think you are close to your final solution.
Adam
Adam 2014년 8월 26일
Hi ,
Thanks. My data points are symmetric (Fig.1) but when I bin these data using the previous code I obtain another data which are not perfectly symmetric (Fig. 2). Do you know why ? I kindly appreciate your help.
the cyclist
the cyclist 2014년 8월 26일
I suppose it is either
  • the way the bin edges are defined, they are not centered around zero, OR
  • the way MATLAB treats values that are exactly on the bin edge, it consistently puts them to one side, leading to asymmetry.
laura9510
laura9510 2017년 1월 31일
Jumping in years later but if I was looking to average within bins, is using accumarray possible in conjunction with another function?

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