change the first digits when ends with 5959
조회 수: 3 (최근 30일)
이전 댓글 표시
Hey, I've got a doubt. I have a string of numbers that go from 0000 to 5959(First two are the minuts and the other two the seconds), when it reaches another time 0000 I wanted to add a unit that goes from 1 to 23(that indicates the hours). I have added this line of code:
T_Hour_1 = '00'+t1; % it gives us t1 with two 00 that indicates the hour
then I got this lines of code that changes the string of T_Hour_1 to dur.
DN1 = str2double(t1);
dur1 = minutes(floor(DN1/100)) + seconds(mod(DN1,100)); % separar en minutos y segundos
[~, M1, S1] = hms(dur1); % Dar tiempo en 2 variables, utilizar M1 para crear rangos
Before doing DN1 I would like to add the numbers from 0 to 23 in front of the others.
How could I do it?
Thank you for your help!!
댓글 수: 0
채택된 답변
Stephen23
2021년 9월 21일
편집: Stephen23
2021년 9월 21일
Rather than messing around with strings you should probably just work with duration objects or numeric arrays.
S = ["000000";"000059";"000100";"000159";"005959";"000000";"005959";"000000";"005900"]
D = duration(strcat(extractBefore(S,3),':',extractBetween(S,3,4),':',extractAfter(S,4)))
D = D + hours(cumsum([0;diff(D)<0]))
댓글 수: 4
Stephen23
2021년 9월 21일
"could you explain to me the second line of code you gave me"
That line locates where the difference in duration is negative (i.e. the duration jumps from a larger value to a smaller value). It then uses CUMSUM on those jump points to create a vector of hourly increments.
If you do not understand how code works then take it apart and look at all of the intermediate results:
S = ["0000";"0059";"0100";"0159";"5959";"0000";"5959";"0000";"5900"];
D = duration(strcat('00:',extractBefore(S,3),':',extractAfter(S,2)))
V = diff(D) % difference between adjacent durations.
W = V<0 % locations where longer duration jumps back to shorter duration.
X = [0;W] % pad with zero.
Y = cumsum(X) % create numeric list of hourly jumps
Z = hours(Y) % convert to duration.
D = D + Z % add to the original data
추가 답변 (1개)
Steven Lord
2021년 9월 20일
Is there a reason you're starting with string data first rather than using a duration array from the start?
d = minutes(0:0.25:60);
d.Format = 'hh:mm:ss';
d(1:5)
d(end-4:end)
댓글 수: 2
참고 항목
카테고리
Help Center 및 File Exchange에서 Dates and Time에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!