Matlab如何将cell中的矩阵进行合并？

Rule3={[3;2] [3;5] [4;2] [4;5] [5;2]};

请问如何判断Rule3中的矩阵第一行第一列是否相同，若是相同则要将两个矩阵合并，比如[3;2]∪[3;5]=[2;3;5]，[4;2]∪[4;5]=[2;4;5]，[5;2]没有于第一行第一列相同的数字5，所以直接保留。

最终，Rule3变成{[2;3;5][2;4;5][5;2]}。希望给出一个相对通用的答案，以为每次循环后，Rule3都会改变。

如有知道，还请不吝赐教，感谢！！！

[Jan]

An automatic translation:

Rule3={[3;2] [3;5] [4;2] [4;5] [5;2]};

How to judge whether the first row and the first column of the matrix in Rule3 are the same. If they are the same, merge the two matrices, such as [3;2]∪[3;5]=[2;3;5],[4; 2]∪[4;5]=[2;4;5], [5;2] does not have the same number 5 in the first row and first column, so keep it directly.In the end, Rule3 becomes {[2;3;5][2;4;5][5;2]}. I hope to give a relatively general answer, thinking that Rule3 will change after each loop.If you know, please feel free to enlighten me, thank you! !

Answer 1

[Jan]

R = {[3;2], [3;5], [4;2], [4;5], [5;2]};

nR = numel(R);
f  = true(1, nR);
for iR = 1:nR
   if f(iR)                               % If element was not disabled before
      a = R{iR}(1);                       % 1st element
      for jR = iR + 1:nR                  % Loop over following elements
         if f(jR)                         % If element was not disabled before
            if a == R{jR}(1)              % Compare 1st element
              R{iR} = [R{iR}; R{jR}(2)];  % Append contents
              f(jR) = false;              % Disable elemen for further tests
            end
         end
      end
   end
end
R = R(f);                                 % Crop disabled elements
celldisp(R)

 
R{1} =
 
     3
     2
     5

 
 
R{2} =
 
     4
     2
     5

 
 
R{3} =
 
     5
     2