Transforming a character double into date format

I have a character (double) vector taken from a txt file corresponding to a timestamp of some measurement data, an example of a character is:

197709131435

I want to transform this into a date format eg: 1977 is the year, 09 month, 13 day, 14:35 time. This is to properly separate my data and find daily and seasonal trends.

I tried changing the character into a string and using the datetime function with the input format I want but it didn't work. How can I do this?

Answer 1

[s pernot]

datetime('197709131435', 'InputFormat', 'yyyyMMddHHmm')