# How do I fit a surface to this data properly?

조회 수: 3(최근 30일)
Pablo Fernandez 2021년 9월 16일
댓글: Pablo Fernandez 2021년 9월 19일
Hi,
I have a set of datapoints (x,y,z) to which I want to fit a surface. I dont have a mathematical expression for the surface, so I tried to use the linear interpolation as in:
PTSGRID = 256;
xs = min(x):(max(x)-min(x))/(PTSGRID-1):max(x);
ys = min(y):(max(y)-min(y))/(PTSGRID-1):max(y);
[xq, yq] = meshgrid(xs,ys);
zq = griddata(x,y,z,xq,yq,'linear');
plot3(x,y,z,'mo')
hold on
mesh(xq,yq,zq);
However the fitted surface takes very strange values where there is no data defined, very different from what I would visually expect. Take a look for example at this figure, and the zone I circled:
How can I fit in a better way to avoid this behavior?
Thanks!
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Pablo Fernandez 2021년 9월 17일
Attached to the original post!

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### 답변(2개)

KSSV 2021년 9월 16일
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Pablo Fernandez 2021년 9월 16일
Yes, I understand.
The specific point in my questions is how to get rid of the artifacts that appear when I try to interpolate the points in my dataset.

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darova 2021년 9월 19일
I don't have this problem
x = s.x;
y = s.y;
z = s.z;
xx = linspace(min(x),max(x),20);
yy = linspace(min(y),max(y),20);
[x1,y1] = meshgrid(xx,yy);
z1 = griddata(x,y,z,x1,y1);
Warning: Duplicate data points have been detected and removed - corresponding values have been averaged.
mesh(x1,y1,z1)
##### 댓글 수: 1표시숨기기 없음
Pablo Fernandez 2021년 9월 19일
You are not seing the effect in that plot because you are evaluating the interpolation in few points. The reason for the interpolation is to evaluate between the data lines. Try changing 20 for 256 in xx and yy definitions and you will notice the effect when plotting.
Regards

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R2020a

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