how to develope loop to save the 'n' elements from the vectors

clc;
clear;
A= [14,51,2,15,........,7 ] % this is known
p1=A[1]
p2=A[2]
.
.
.
.
.
pn=A[n]
%%% i need to use p1,p2,p3,...pn in another equation. so i dont know to to save this elements from A. how to use loop to that it automatically get saved for n elements

답변 (2개)

Matt J
Matt J 2021년 9월 15일

2 개 추천

It is not a good idea to store A(i) in separate variables. You should probably just write your equation in terms of vector operations on A, which you already have.

댓글 수: 2

Hii Matt, thank you
i fully agree with you. actually, i am a beginner, so no idea how to use.
if my function is in this way
fun= p1*r^2+p2*ln(r)+p3*cos(theta)/r+p4*sin(theta)/r+(pn*r^(-n+2))*cos(n*theta)
then how to do that?
A(1)*r^2+A(2)*ln(r)+A(3)*cos(theta)/r+A(4)*sin(theta)/r+(A(n)*r^(-n+2))*cos(n*theta)

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Although it is not prefered to name variables in a loop but if you striclty want to do this in loops than you can use eval(). Note that using this method is NOT RECOMMENDED. It has been said many times in this forum and by MATLAB itself.
clc;
clear;
A= [14,51,2,15,7]
A = 1×5
14 51 2 15 7
for col = 1:1:size(A,2)
eval(['p',num2str(col),'=A(',num2str(col),')'])
end
p1 = 14
p2 = 51
p3 = 2
p4 = 15
p5 = 7

댓글 수: 1

Stephen23
Stephen23 2021년 9월 15일
편집: Stephen23 2021년 9월 15일
Note that this is slower and more complex than simply using the vector directly.

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2021년 9월 15일

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2021년 9월 15일

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