Trying to use a for loop to calculate years with an IF statement but it seems to ignore it.
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So the program is meant to stop if balance >= 500000 but it seems to soldier on until it runs out of months. Use of a for loop is required.
clear; close all; clc
balance(1) = 1000;
contribution = 1200;
M = 1; % month ticker
years = 12/M;
interest = 0.0025;
for M = 1:300
if balance(M) >= 50000 %balance(M)
end
M = M + 1; % you need to increment months + 1 every cycle
balance(M) = balance(M-1) + interest*balance(M-1) + contribution;
end
%Balance %This will display the final Balancefprintf('%g Months until $500000 reached\n', M);
fprintf('%g Years until $500000 reached\n', years);
format bank
plot(balance);
grid on
ytickformat('usd')
title('Saving 3% compound')
xlabel('Months')
ylabel('Saving balance')
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Jan
2021년 9월 13일
편집: Jan
2021년 9월 13일
Either
for M = 2:300
if balance(M) >= 50000 %balance(M)
break; % Leave the for M loop
end
% NOPE ! M = M + 1; % you need to increment months + 1 every cycle
balance(M) = balance(M-1) + interest*balance(M-1) + contribution;
end
or
for M = 2:300
if balance(M) < 50000 %balance(M)
% NOPE ! M = M + 1; % you need to increment months + 1 every cycle
balance(M) = balance(M-1) + interest*balance(M-1) + contribution;
end
end
If you do not know in advanve how log a loop runs, a while loop is nicer:
M = 2;
while M <= 300 && balance(M) < 50000
balance(M) = balance(M-1) + interest*balance(M-1) + contribution;
M = M + 1;
end
While the counter M must be increased in the while loop, this is done in the for loop automatically.
[EDITED] M starts at 2 now.
댓글 수: 4
Jan
2021년 9월 13일
This looks strange:
M = 1; % month ticker
years = 12/M; % Are you sure that 12/1 is the number of years?!
% The usual definition is Months / 12
for M = 1:300
if balance(M) >= 500000 %balance(M)
break; % Leave the for M loop
end
% No! Do not increase the loop counter inside the
% body of a FOR loop:
% M = M + 1;
My code failed, because accessing balance(M - 1) requires the loop to start at M=2. I've edited my answer.
Label = max(balance) is not useful before the loop, because balance contains 1 value only.
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