Moving mean/std based on number of NaN

Hello,

Is there a way to compute movstd but replace with NaN if the window includes 2 or more NaN?

A=[4, 8,6,3,NaN,NaN,-1,9,4,5]'

This window is 4

M=movstd(A,4,'omitnan','Endpoints','discard')

M is

2.217355783

2.516611478

2.121320344

2.828427125

7.071067812

5

4.11298756

With the condition to replace with NaN if the window includes 2 or more NaN

M should be

2.217355783

2.516611478

NaN

NaN

NaN

5

4.11298756

Answer 1

[Matt J]

A=[4, 8,6,3,NaN,NaN,-1,9,4,5]';

M=movstd(A,4,'omitnan','Endpoints','discard');
idx=movsum(isnan(A),4,'omitnan','Endpoints','discard')>=2;
M(idx)=nan

M = 7×1

2.2174 2.5166 NaN NaN NaN 5.0000 4.1130

[Dave]

Danke

Answer 2

[Walter Roberson]

A=[4, 8,6,3,NaN,NaN,-1,9,4,5]'

A = 10×1

4 8 6 3 NaN NaN -1 9 4 5

window = 4;
M=movstd(A,window,'omitnan','Endpoints','discard')

M = 7×1

2.2174 2.5166 2.1213 2.8284 7.0711 5.0000 4.1130

An = isnan(A.');
starts = strfind([false, An], [false,true,true])

starts = 5

stops = strfind([An,false], [true,true,false])+1

stops = 6

M(unique(cell2mat(arrayfun(@(start,stop) start-window+2:stop-1, starts, stops, 'uniform', 0)))) = nan

M = 7×1

2.2174 2.5166 NaN NaN NaN 5.0000 4.1130