How to plot function

조회 수: 2 (최근 30일)
Hardik
Hardik 2014년 7월 29일
댓글: Ben11 2014년 7월 30일
I'm working on a question where I am executing a function y = staircase(x) where
y = [ 0 if x <= 1 , 1 for 1<x<=2 & 2 if 2<x ]
So far I have;
function y = staircase(x)
for x = -3:0.01:3
if x <= 1
y = 0;
elseif x > 1 && x <= 2
y = 1;
else x > 2;
y = 2;
end
end
My question is how do I plot such a function?

답변 (3개)

Ben11
Ben11 2014년 7월 29일
A lazy way would be like this:
figure
hold on
plot((-3:0.01:1),0,(1.01:0.01:2),1,(2.01:0.01:3),2,'LineWidth',2)
line('XData',[1 1],'YData',[0 1],'LineStyle',':');
line('XData',[2 2],'YData',[1 2],'LineStyle',':');
hold off
which gives this:
Do you need to write the plotting part in your function or you simply want to look at the staircase for some other purpose?

Azzi Abdelmalek
Azzi Abdelmalek 2014년 7월 29일
편집: Azzi Abdelmalek 2014년 7월 29일
x is an input argument, you can't assign values to x inside the function.
save this function as staircase.m
function y = staircase(x)
for k=1:numel(x)
if x (k)<= 1
y(k) = 0;
elseif x(k) > 1 && x(k) <= 2
y(k) = 1;
else x(k) > 2
y(k)= 2;
end
end
Then in Matlab Windows Command or in a new script write
x=-3:0.1:3 ; %assign values to x
y = staircase(x);
plot(x,y)
  댓글 수: 4
Hardik
Hardik 2014년 7월 30일
When I run the script with the addition of the numel, matlab gives me an error saying Not enough input arguments.
Ben11
Ben11 2014년 7월 30일
As Azzi suggested, you have to define x before you call staircase. I ran his code and it works well. Do the following:
1) Define x in the command window
x = -3:0.1:3;
2) Once this is done, you can then call staircase(x) and plot the result:
y = staircase(x);
plot(x,y)

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Star Strider
Star Strider 2014년 7월 29일
I built my own staircase function, because I didn’t want to create a separate function file.
This is how I plotted it:
x = -3:0.01:3;
staircase = @(x) [(0*(x <= 1)) + (1*((x > 1) & (x <= 2))) + (2*(x > 2))];
sc = staircase(x);
figure(1)
plot(x, sc)
axis([xlim -0.5 2.5])
The axis call makes it visible over its range.

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