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Azzi Abdelmalek
Azzi Abdelmalek 2014년 7월 25일
A=[1 2 10 3]
Try
max(A) % The greatest value in A
and
length(A) % number of element in A

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Josh
Josh 2014년 7월 25일

0 개 추천

Thank you, that's what I thought. I was working a problem and the resulting histogram is the same whether I use max(X) or length(X) which did not make sense to me, but since I was creating a vector using X(i) = sum(rand > cumsum(p))+1, I suppose in this case max(X) and length(X) are the same.

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No. X(i) can be any integer value between 1 or and length(p)+1. Those values are independent of the max value of X since you could have different X(i). We don't know how long X is. For example, maybe X = [10, 30, 100, 4, 16], so length(X) = 5 while max(X) = 100. Rand is different for each i so that's why the values of X could be different for each i, and thus the max value is independent of the length, except in very coincidental cases.

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카테고리

도움말 센터 및 File Exchange에서 Histograms에 대해 자세히 알아보기

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2014년 7월 25일

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2014년 7월 26일

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