Opening excel file not on path using winopen GUI

Hi,
After running a simulation, I save the data to an excel file with the name of that file saved into handles.file, defined when the GUI is initialized. The user then presses a pushbutton to open the file using
WINOPEN([handles.file, '.xls']);
This all works fine.
However, this only worked when the GUI and the simulation the GUI ran were on the same path. If the simulation isn't in the same folder as the GUI, the excel file is written to the same directory as the sim, and so the GUI can't find the excel file when I try to open it.
How do you alter the above code so that it looks in the right place? Something like
winopn('C:/myfiles/',[handles.file, '.xls'])
Although this obviously doesn't work
Thanks,
Henry

카테고리

도움말 센터File Exchange에서 Environment and Settings에 대해 자세히 알아보기

질문:

2014년 7월 25일

답변:

2014년 7월 25일

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