matrix shape is incorrect??

Hi, I have the following code which will give me values of F along a plane surface. It should give me a vecor matrix in a 1x9 shape. However the resulting matrix appears to be a 9x1 shape.

for Q=1:length(Phi)
if Phi(Q)<0;
    F(Q)=1;
else
F(Q)=(2/pi) .* acos(exp(-(((B/2) .* (1-(r_over_R(Q)))) ./ ((r_over_R(Q)) .* sin(relative_wind(Q))))));      % Tip Loss Factor
end;
end;
Does anybody know how I can change this? Thanks.

Answer 1

[Wayne King]

You don't give us all the variables here so we can't tell you how to change in the loop, but the simple thing to do is at the end of the loop (after the final "end"), just do

F = F';

The above assumes that F is real-valued. If F is complex-valued and you don't want to conjugate the elements, do

F = F.';

[Michael Haderlein]

That's one option, or you just preallocate F by

F=zeros(size(Phi));

Then you'll get the same shape, improved memory efficiency and no more a warning at the respective line.

Best regards,

Michael

Answer 2

[Azzi Abdelmalek]

It's simple, just transpose the result

A=A'