# hough peaks not symmetric for rectangle

조회 수: 2(최근 30일)
Michael scheinfeild 2014년 7월 8일
답변: Michael scheinfeild 2014년 7월 9일
hello i use hough transform for rectangle the peaks should be symetric. but they are not symmetric around theta angle based on
%%just test
close all;clear;
m=zeros(200,300);
m=logical(m);
m(50,30:190)=1;
m(100,30:190)=1;
m(50:100,30)=1;
m(50:100,190)=1;
%m=imrotate(m,45);
stats=regionprops(m,'BoundingBox');
bx = stats.BoundingBox;
m=imcrop(m,bx);
figure(1),imagesc(m)
[H, T, R] = hough(m);
figure(2)
'InitialMagnification','fit');
title('Hough Transform of Image');
xlabel('\theta'), ylabel('\rho');
axis on, axis normal, hold on;
colormap(hot);
Hv=H(:);
mxH = 0.2*max(Hv);
ii=find(Hv>=mxH);
[aa bb] = ind2sub(size(H),ii);
figure(4),imagesc(T,R,H),hold on,plot(T(bb),R(aa),'gs','MarkerSize',10,'MarkerFaceColor',[0.5,0.5,0.5]);

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### 채택된 답변

Anand 2014년 7월 8일
The symmetry should hold only for rectangles centered at the origin. I just skimmed the paper, but it seems to describe a technique where the search space is centered around the peak you are currently looking at. In MATLAB, the origin is at the top left pixel in the image.
When the rectangle is at the center, rho1=-rho2 and rho3=-rho4. This is not the case when the rectangle isn't centered at the origin.

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### 추가 답변(1개)

Michael scheinfeild 2014년 7월 9일
yes you right i suppose i need to write the hough transform by myself with moving window , i suppose the center should be at center of mass of the shape

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