Image Reconstruction:Phase vs. Magnitude
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Figure 1.(c) shows the Test image reconstructed from MAGNITUDE spectrum only. We can say that the intensity values of LOW frequency pixels are comparatively more than HIGH frequency pixels. f(x,y) is image function and F(u,v) is its 2D Fourier transform
f(x,y)= ∑_(u=0)^(U-1)∑(v=0)^(V-1)\ F(u,v) exp^(1j*2Π*xu)/M) e^(1j*2Π*(vy)/N) --(1)
Figure 1.(d) shows the Test image reconstructed from PHASE spectrum only. We can say that intensity values of HIGH frequency (edges,lines) pixels are comparatively more than LOW frequency pixels.
f(x,y)= ∑_(u=0)^(U-1)∑(v=0)^(V-1)\ exp(j*angle(u,v)) exp^(1j*2Π*xu)/M) * e^(1j*2Π(vy)/N)--(2)
i want to ask that in phase only reconstruction part why do i get only edges or lines,why not low frequency components?? because from the 2nd equation i am not getting any idea that only edge like features are emphasized......

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Gnaneswar Nadh satapathi
2014년 6월 27일
refer Fourier Transform for this
ramdas patil
2014년 6월 28일
편집: ramdas patil
2014년 6월 28일
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도움말 센터 및 File Exchange에서 Image Filtering에 대해 자세히 알아보기
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