A=[ 1 1 2 2 3 3 3];
unique(A)=[1 2 3]; but I want to find the duplicates that are not the first occurrence. i.e x=[2 4 6 7]; I typed help unique but I couldn't figure out if I and J reported by this function helps with my purpose.I know that I can program it but i want to be as efficient as possible in my codes to reduce the running time.

 채택된 답변

the cyclist
the cyclist 2011년 8월 5일

4 개 추천

Here is one way:
[uniqueA i j] = unique(A,'first');
indexToDupes = find(not(ismember(1:numel(A),i)))

추가 답변 (1개)

Jan
Jan 2011년 8월 5일

12 개 추천

Another solution:
A = [1 1 2 2 3 3 3];
[U, I] = unique(A, 'first');
x = 1:length(A);
x(I) = [];

댓글 수: 2

Oleg Komarov
Oleg Komarov 2011년 8월 5일
Clever and simple.
Jan
Jan 2011년 8월 5일
I'm inspired by Marsaglia's KISS random number generator: "Keep It Simple Stupid".

댓글을 달려면 로그인하십시오.

카테고리

도움말 센터 및 File Exchange에서 Communications Toolbox에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by