# Extra term in "min" function in while loop

조회 수: 6(최근 30일)
Adam 2014년 5월 27일
댓글: Adam 2014년 5월 27일
I was given a piece of code to work on and edit but I'm running into a few errors because I am unsure what this extra piece of term means in the code, the code looks like this:
while DC1(1,j) ~= min(DC1(:,450:Xep)),DC1(1,j);
Xbp = j;
j=j+1;
end
I can understand the fact that DC1 is searching for the position of the minimum value term in itself by comparing it using the "min" function. What I do not understand is why there is that extra
",DC1(1,j)" bit. Do you know what it is? Thanks.

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### 채택된 답변

Roger Wohlwend 2014년 5월 27일
The min function compares the vector DC1(:,450:Xep) to the scalar DC1(1,j). The result is a vector that is identical to DC1(:,450:Xep) except that all values that are greater than DC1(1,j) are replaced by DC1(1,j). Then this vector is compared to DC(1,j).
If Xep > 451 then DC1(:,450:Xep) is a vector and as I just wrote the result of the min function is a vector. When you compare a scalar to a vector you get a vector of logical values, but to control a loop you should not use a vector of logicals but only one single logical. If you provide a vector, I'm not completely sure, what Matlab does. I would avoid it because you risk that the code does not always do what it should. Perhaps the guy who wrote the code meant something like this:
while DC(1,j) ~= min(DC1(:,450:Xep))
That would make more sense.
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Adam 2014년 5월 27일
well originally when I found the code it was simply on the next line like this:
while DC1(1,j) ~= min(DC1(:,450:Xep))
,DC1(1,j);
But because of that "," i figured he ment to leave it on the first line but took it down for keeping the code clean or prevent lines from getting to long.

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### 추가 답변(2개)

lvn 2014년 5월 27일
I guess it is a remainder of some old code. It can be removed, it does nothing!
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George Papazafeiropoulos 2014년 5월 27일
The extra
,DC1(1,j)
bit is the next command. You can erase the initial comma and press enter to get it in the next line.

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