필터 지우기
필터 지우기

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about logical operator in if!

조회 수: 1 (최근 30일)
chan
chan 2014년 5월 25일
마감: MATLAB Answer Bot 2021년 8월 20일
This is my code
y = input('choose','s');
if y == 'a1' | y == '1a'
disp('win')
else
disp('lost')
end
I would like to ask that when I use this, while I am run this program, I type only a or only 1 it also display win, like i type 1a or a1 . explain to me, or me have other ways to write the code, I do not need to add elseif more.
Thanks!

답변 (1개)

Matt J
Matt J 2014년 5월 25일
편집: Matt J 2014년 5월 25일
Use strcmp()
if strcmp(y,'a1') || strcmp(y,'1a')
disp('win')
else
disp('lost')
end
As for understanding what's happening currently, observe the result of each of your sub-expressions, and the vectors of logical data they produce, when y='1',
>> y='1';
>> y == 'a1'
ans =
0 1
>> y == '1a'
ans =
1 0
>> y == 'a1' | y == '1a'
ans =
1 1
Since (y == 'a1' | y == '1a') produces a vector of trues, the whole if statement evaluates to true. As mentioned in "doc if",
" An evaluated expression is true when the result is nonemptyand contains all nonzero elements (logical or real numeric). Otherwise,the expression is false. "
  댓글 수: 5
Matt J
Matt J 2014년 5월 26일
편집: Matt J 2014년 5월 26일
to see if two things are equal use isequal, ... isequal(y,'a1')
Be careful when using isequal to compare strings. It doesn't check that both arguments are class char, e.g.,
>> isequal(':',58)
ans =
1
whereas,
>> strcmp(':',58)
ans =
0
Matt J
Matt J 2014년 5월 26일
so mean we cannot use the simple condition, right? y == 'a1' | y == 'a1'
You can use these kinds of comparisons when they are appropriate to what you are doing. For example, suppose I want to remove all the spaces in a string,
>> y='This is a short string'; y(y==' ')=''
y =
Thisisashortstring

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