finding repetition numbers in array.
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A=[1;1;1;2;2;2;2;3;3;3]; %double
%I wanna known how many times 1,2,3 are exist in A matrix with orderly like that;
rep=[3;4;3]; %w.r.t A matrix (3 times 1, 4 times 2 and 3 times 3)
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Neuroscientist
2014년 5월 15일
you can have something like this:
A=[1;1;1;2;2;2;2;3;3;3];
B = unique(A); % which will give you the unique elements of A in array B
Ncount = histc(A, B); % this willgive the number of occurences of each unique element
best NS
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shubham gupta
2019년 2월 26일
simple and clear explaination. thank you sir, now i am able to solve my problem.
추가 답변 (1개)
Jos (10584)
2014년 5월 15일
Your question title (finding repetition numbers) and your question text ("how many times exist") are open for ambiguity.
For A = [1 1 4 1 1 1] should the algorithm return [5 1], [5 0 0 1] or [2 1 3]?
A = [1 1 4 1 1 1]
% [5 1] case
R = histc(A,unique(A))
% [5 0 0 1] case
R = histc(A,1:max(A))
% [2 1 3] case
N = diff([0 find(diff(A)) numel(A)])
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omran alshalabi
2022년 8월 28일
hi, thank you for your detailed answer,
I have another question, can I get some case like,
% [1 4 1] case
MarKf
2022년 10월 22일
removing duplicates then
A = [1 1 4 1 1 1];
b = A([true, diff(A)~=0])
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