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Counting the from when data changes to 0 then changes back to a number
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This is my code:
%% Import data
numfiles = 54; % number of excel files mydata=cell(numfiles,1); % defining size of mydata d=dir('Trial*.csv');
for i=7:length(mydata) % loop to import mutliple excel files
try
mydata{i} = xlsread(d(i).name); % import files into mydata
catch
disp([d(i).name 'read failed'])
end
myfilename = sprintf('Trial%02d.csv', i); % define file name
mydata{i} = xlsread(myfilename); % import files into mydata
%% Perfrom Calculations
%%Define variables
a= 9.81; % acceleration
fps = 250; % frames per second
%%Calculate Jump Height
no_of_zeros(i,1) = size(mydata{i,1},1) - nnz(mydata{i,1}(:,5)); %number of zeros
no_of_frames = (no_of_zeros(i,1)/4); % number of frames
time = ((no_of_frames/fps)/2); % time up
jumph(i,1)=((a*(time*time))/2); % jump height
Looking at the calculate jump height, it calculates correctly for the first 2 trials but then gives large over estimations for nealry all the other trails. It was a while ago I wrote this could someone clarify this line of code for me as this is where the trouble lies, I'm unsure with the ,1.
no_of_zeros(i,1) = size(mydata{i,1},1) - nnz(mydata{i,1}(:,5)); %number of zeros
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Azzi Abdelmalek
2014년 5월 13일
Franchesca, zeros are also numbers. Your question and your comment are different. Do you need to count the number of zeros or how many time they switch from zero to non zero?
답변 (1개)
Azzi Abdelmalek
2014년 5월 13일
편집: Azzi Abdelmalek
2014년 5월 13일
a=[1 1 0 0 4 5 0 0 7 4 7 0 0 0 7]
idx=[ 1 a~=0 1]
ii=strfind(idx,[1 0])
jj=strfind(idx,[0 1])
out=jj-ii
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