Deleting Triangulation Entries from a Delaunay Triangulation Based on Indices Given by a Logical Array

Hello,

I am using Delaunay Triangulations to map a 3D space. Given certain criteria, I select a certain number of points to be removed both from my coordinates vector and the triangulation matrix. I am using a logical array to define the coordinates vector indices to remove, now I want to use that directly to detect which rows of the triangulation contain those indices and delete them. A little example:

A = [1 2 3;4 5 6;7 8 9;10 11 12]; % Coordinate Matrix
bound = [5 3 3]; % Spatial Bounds
ids = bound(1,1) <= A(:,1) & bound(1,2) <= A(:,2) & bound(1,3) <= A(:,3); % logical operator

This code gives

ids = [0 0 1 1]

This means I can delete the coordinates not satistying my boundaries with

A(ids,:) = [];

But how can I search for the indices 3 and 4 (the one resulting from the logical operation) inside a big Triangulation matrix (of size n*4) and delete every row containing one of those indices? I obviously only care about rows.

Thanks

[the cyclist]

Are you saying that if

T = [1 2 6 7; 1 3 6 7; 1 4 6 7; 1 5 6 7];

you want to remove the second and third rows, because they contain the numbers 3 or 4?

[Alessandro]

Exactly!

Answer 1

[the cyclist]

If my comment above is a correct interpretation of what you want, then this code will do it:

T(any(ismember(T,find(ids)),2),:) = [];

[Alessandro]

Works perfectly, thanks!