Renaming parameters in a loop, Comparing Z-Scores

I have a 48x64x41 array where the dimensions are vertical x horizontal x time. I need to compare the z-score array values for times 1 to 41, ie:

zscores(array(:,:,i)) for i=1:41

and find the time of the array with the greatest values.

I am attempting to use a for loop to assign the array at different times to a parameter:

for i=1:41 z=zscore(array(:,:,i)) end

However, obviously like that z is reassigned each time the loop iterates. What I would like to do is have 41 new "z"'s, corresponding to each time.

i.e

at the end of the for loop there will be z1 through z41, corresponding respectively to zscore(array(:,:,1)) to zscore(array(:,:,41).

I then plan to compare these 41 results to find the time at which the array values are the greatest.

Therefore, my questions are: -How can I change the value of z to be z(i), that is z1 through z41 are the outputs at the end of the for loop?

-Does anyone have a smarter suggestion as to how I can obtain the location time of the greatest array values?

Thank you in advance for your replies!

Answer 1

[the cyclist]

This is better. [I had not realized that zscore() is a MATLAB function.]

arraySize = size(array);

z = zeros(size(array));

for i = 1:41
    z(:,:,i) = zscore(array(:,:,i));
end

Answer 2

[the cyclist]

Use a cell array:

% Preallocate  
z = cell(41,1);

% Run loop
for i=1:41
    z{i} = zscore(array(:,:,i))
end

[A]

Thanks for your response.

I tried this before, this is the errory that is returned:

??? In an assignment A(I) = B, the number of elements in B and

I must be the same.

Error in ==> viewer3d at 34

z(i)=zscore(invol(:,:,i));

This is what my code looks like:

z = zeros(41,1);

for i=1:41 %tau

z(i)=zscore(invol(:,:,i));

end

[Walter Roberson]

You did not use the code that the cyclist did. the cyclist used {i} in the assignment, but you used (i) in the assignment.

[the cyclist]

In fairness to Amina, I did several quick edits to this answer, while I (too?) hastily posted answers, before I realized that each "zi" was not expected to be a scalar. In the first incarnation, I did not use cell arrays. [Regardless, my other answer, which was accepted, was better.]