Scatter plot does not display point 0,0 when double precision

I have the following code which works as intended, plotting 3 points.
x = [0 0; 12 0; 6 6];
scatter(x(:,1), x(:,2), 100, 'fill');
However, when I interject the following line
x = 1.01 * x;
which effectively turns everything into double precision, then the point 0,0 does not display
why is that, and how can I make it so that it also displays?
Thanks in advance!

 채택된 답변

José-Luis
José-Luis 2014년 4월 23일
Trying to understand the mess that is Matlab's graphics engine is a real pain. I can only recommend a workaround:
x = [0 0; 12 0; 6 6];
figure(1)
scatter(x(:,1), x(:,2), 100, 'fill');
x = 1.01 * x;
figure(2)
scatter(x(:,1), x(:,2), 100, 'fill'); %Now readjust the axes so you can see what you actually plotted:
set(gca,'XLim',x([1 2],1)); %you can use min() max() in order to avoid hard coding the indices.
set(gca,'YLim',x([1 3],2));

추가 답변 (3개)

AJ von Alt
AJ von Alt 2014년 4월 23일
This looks like an issue with the Painters renderer. Switching to OpenGL resolves the issue on my end.
x = [0 0; 12 0; 6 6];
figure('renderer','OpenGL')
scatter(x(:,1), x(:,2), 100, 'fill');
y = 1.01 * x;
figure('renderer','OpenGL')
scatter(y(:,1), y(:,2), 100, 'fill');

댓글 수: 2

This also works! Although it goes beyond my ability to understand this, it is a cleaner solution. Thanks!
P.S. I think you need the
figure('renderer','OpenGL')
line only once, otherwise it creates an additional empty plot...
The renderer is used to draw the plot in the figure. It is defined independently for each figure so you will need to specify it every time you create one.
You can change the renderer of the current figure to "OpenGL" using the command:
set( gcf , 'renderer' , 'OpenGL' )

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chris
chris 2014년 4월 23일

0 개 추천

Thanks for your answer. Attached image is how my system behaves.
chris
chris 2014년 4월 23일

0 개 추천

This works! It is weird though why the original version doesn't behave seamlessly.
Anyways, thanks everybody for the help.

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