Why is loop time execution better than vectorized form in this case?
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Hello everyone,
At first, I had the following code:
for ii = 1:numel(data.classes)
switch data.classes{ii}
case 1
data.classes{ii} = 'case 1';
% Active classes
case 2
data.classes{ii} = 'case2';
otherwise
disp('Invalid case.');
end
end
However, I know that vectorized code is preferred instead of loops, so I changed it to
case1Found = ismember(data.classes, case1Members);
case2Found = ismember(data.classes, case2Members);
data_.classes(case1Found) = {'case1'};
data_.classes(case2Found) = {'case2'};
When comparing their performance (execution time) I was surprised to see that the first option, with loops was twice as fast than the vectorized option (0.014688 s vs. 0.029204 s)!
Why is this? Thanks ;-) !
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Daniel Shub
2011년 7월 27일
1 개 추천
The gains in efficiency from vectorization are not always that substantial anymore (and can even be negative) since loops in MATLAB have become much faster over the years, thanks, I believe, to the JIT accelerator.
카테고리
도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
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