How to reshape a 2D to 3D matrix without using loops (reshape) and keeping a particular order of the elements// Wrong arragement of elemts after using "reshape"

조회 수: 3 (최근 30일)
I've a problem using the reshape function. I've a Matrix A: A =
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
I want to change it to a 3D Matrix with the size 4x4x3. When I use reshape like this:
A2=repmat(A,4,4,3); the result is:
A2(:,:,1) =
1 1 1 2
5 5 5 6
9 9 9 10
13 13 13 14
A2(:,:,2) =
2 2 3 3
6 6 7 7
10 10 11 11
14 14 15 15
A2(:,:,3) =
3 4 4 4
7 8 8 8
11 12 12 12
15 16 16 16
The result I want though is:
A2(:,:,1) =
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
A2(:,:,2) =
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
A2(:,:,3) =
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
In the real data set I've different values, I just chose (1:16) 3 Times to show in what order I want to rearrange the data/Matrix.
Thanks a lot!

채택된 답변

Azzi Abdelmalek
Azzi Abdelmalek 2014년 3월 30일
편집: Azzi Abdelmalek 2014년 3월 30일
A=[1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16]
A2=permute(reshape(A',4,4,[]),[2 1 3])

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by