How do you write a matlab function that identifies if a string is a palindrome or not?
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So far I've got ...
string = input('What is your number: '); disp(fliplr(string))
if string == fliplr(string) disp('Your number is a PALINDROME') else disp('Your number is NOT A PALINDROME') end
And now I'm stuck
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채택된 답변
Image Analyst
2014년 3월 30일
Almost. Try this:
string = input('What is your string: ', 's');
fprintf('Your string = %s\nFlipped, it = %s\n', string, fliplr(string));
if string == fliplr(string)
disp('Your number is a PALINDROME')
else
disp('Your number is NOT A PALINDROME')
end
댓글 수: 4
Star Strider
2014년 3월 30일
That’s my all time fave!
Probably need to remove all blanks as well before flipping and doing the comparison.
Image Analyst
2014년 3월 30일
True.
string = lower(string);
string(string == ' ') = '';
추가 답변 (3개)
sesha sai
2020년 9월 26일
function [ palindromic ] = palindrome( string )
if length(string) < 1
palindromic = logical(1);
return;
end
if string(1) ~= string(length(string))
palindromic = logical(0);
return;
end
palindromic = palindrome(string(2:length(string)-1));
end
댓글 수: 1
Benjamin Askelund
2016년 10월 19일
편집: Benjamin Askelund
2016년 10월 19일
Hi, I made a code that flipps as well NOT USING fliplr based on "Image Analyst" code. Lots of people ask for this as far as I know
clc
%Ask user for string
A = input('What is your string: ', 's');
%flipp string
B = flip(A);
fprintf('Your word = %s\nflipped word is = %s\n', A, B);
%compare stringA and FlippedString (bool)
if strcmp(A, B) == 1
disp('Your number is a PALINDROME')
else
disp('Your number is NOT A PALINDROME')
end
This code also works for numbers. Just type numbers insted of strings
Sorce: https://se.mathworks.com/help/matlab/ref/flip.html
Signed BDA
댓글 수: 2
Steven Lord
2016년 10월 19일
Lots of people ask for this because it's a fairly easy homework assignment and so it is one that's often assigned in courses where students are being introduced to MATLAB.
Bhuvana Krishnaraj
2020년 1월 9일
편집: Walter Roberson
2024년 1월 10일
x=input('Enter number: ');
temp=x;
y = 0;
while x > 0
t = mod(x,10);
y = 10*y+t;
x = (x-t)/10; %% without this it will give floating value
end
if(y==temp)
disp('The number is palindrome');
else
disp('The number is not palindrome');
end
댓글 수: 1
Walter Roberson
2020년 9월 26일
Suppose the user enters 050. That would certainly appear to be a palindrome. You use input() with no 's' to read it so you get a binary double precision value equal to decimal 50. You proceed to process it numerically and get 10*0 + 5 = 5. But 5 is not 50 so you say No it is not a palindrome. When it should probably be one.
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