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how to draw a rectangle to identify character

조회 수: 3 (최근 30일)
ahmed
ahmed 2014년 3월 29일
댓글: Rik 2021년 7월 14일
This code to draw a rectangle to identify character that I had found (overlay the template in a target).
[name,path] = uigetfile('*.jpg');
image1 = imread([path,name]);
[name,path] = uigetfile('*.jpg');
image2 = imread([path,name]);
if size(image1,3)==3
image1=rgb2gray(image1);
end
if size(image2,3)==3
image2=rgb2gray(image2);
end
% check which one is target and which one is template using their size
if size(image1)>size(image2)
Target=image1;
Template=image2;
else
Target=image2;
Template=image1;
end
% find both images sizes
[r1,c1]=size(Target);
[r2,c2]=size(Template);
% mean of the template
image22=Template-mean(mean(Template));
%corrolate both images
corrMat=[];
for i=1:(r1-r2+1)
for j=1:(c1-c2+1)
Nimage=Target(i:i+r2-1,j:j+c2-1);
Nimage=Nimage-mean(mean(Nimage)); % mean of image part under mask
corr=sum(sum(Nimage.*image22));
corrMat(i,j)=corr;
end
end

답변 (3개)

Image Analyst
Image Analyst 2014년 3월 29일
That's a dangerous way to use size(). Looks like someone needs to read Steve's blog on the use of the size function.
Anyway, I'm not sure what your question is. Do you want to draw a rectangle in the overlay above the image? If so, use plot() or rectangle().
  댓글 수: 2
Image Analyst
Image Analyst 2014년 3월 29일
편집: Image Analyst 2014년 3월 29일
Anyway, you can't find a template in a target by correlation, at least not robustly. Think about it and if you don't know why, ask. You'll need to use normalized cross correlation, as shown in my attached demo.
raha boolat
raha boolat 2021년 7월 14일
It was a wonderful program. Bravo

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ahmed
ahmed 2014년 3월 29일
편집: ahmed 2014년 3월 29일
i want to draw a rectangle in a overlay the full image illuster to identify the character
  댓글 수: 1
Image Analyst
Image Analyst 2014년 3월 30일
Invert your image so that the letters are white and then run the normalized cross correlation code I gave you.

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raha boolat
raha boolat 2021년 7월 14일
편집: Rik 2021년 7월 14일
function obj_det(img_name)
f=imread (img_name);
if (size(f,3) >1)
f=rgb2gray(f);
f_bw=~im2bw(f,graythresh(f));
else
f_bw=~im2bw(f,graythresh(f));
end
f_bw=imfill(f_bw,'holes');
s=bwconncomp(f_bw);
imshow(f);
for i=1:s.NumObjects
ind=s.PixelIdxList{i};
[r,c]=ind2sub(size(f),ind);
min_r=min(r,[],1);
max_r=max(r,[],1);
min_c=min(c,[],1);
max_c=max(c,[],1);
hy=max_r - min_r;
hx=max_c - min_c;
rectangle('position',[min_c,min_r,hx,hy],'EdgeColor','r');
end
end
  댓글 수: 1
Rik
Rik 2021년 7월 14일
@raha boolat This time I edited your answer for you. Next time, please use the tools explained on this page to make your posts more readable.

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