How to delete leading zeros in a row vector in MATLAB?

I have created a function which multiplies two factorials together in MATLAB and the final result is:

0000000000000000000000000000000000000000

0000000000000005127485891768928006848657

3067757467756330382900027197934928341442

4644048874750576347830749966301579885959

6864463688769208320000000000000000000000

00

I need to delete the leading zeros, without deleting the trailing zeros. Anyone know how to do this?

Would help a lot, thanks

[Walter Roberson]

What datatype is that? Is it a 2D character array? Is it a character vector you have wrapped for display purposes?

[Emily]

It is one long vector

[Walter Roberson]

In MATLAB the only way to get a number that long would be by using the Symbolic Toolbox, which would never print leading zeros.

[Emily]

it is a vector, i just put it in the form of a number at the end. I need to know how to get rid of the leading zeros in vector form please?

Answer 1

[Mischa Kim]

If it's a vector of chars, this should do:

 data = regexprep(data,'^0*','')

[Yuchen Xiao]

nice!

Answer 2

[Joseph Cheng]

So I take it is a string array? If it is I would use something like this.

result='000000000123450101010'
mask = ones(size(result));
zero = strfind(result,'0');  %find all the zeros 
mask(zero)=0;  %mask off the zeros 
msb = find(mask~=0); %find what numbers are not zero in the mak
result=result(msb(1):end) %first non zero number to the end of the result is the number.

Answer 3

[Shivam010]

d=[0 0 0 0 0 1 0 0 4 5 0 1]
g=find(d==0)
for i=1:length(g)
    if g(i)==i
        d(1)=[]
    end
end

output:

d =

     1     0     0     4     5     0     1

Answer 4

[Walter Roberson]

S = '0000000000000000000000000000000000000000000000000000000512748589176892800684865730677574677563303829000271979349283414424644048874750576347830749966301579885959686446368876920832000000000000000000000000';

result = S(find(S ~= '0', 1, 'first') : end);