Problem with understanding timestamp read from a binary file using fread

I read a binary file which has the following structure :

struct request
{
  uint32_t timestamp;

    uint32_t clientID;

    uint32_t objectID;

    uint32_t size;

    uint8_t method;

    uint8_t status;

    uint8_t type;

    uint8_t server;

};

the code I used to read this file is :

int_32=[];

int_8=[];

fid = fopen('wc_day6_1','r');

int_32=fread(fid,'4*uint32',4);

frewind(fid);

fseek(fid,16,'bof');

int_8=fread(fid,'4*uint8',16);

A=reshape(int_32,4,[]);

B=reshape(int_8,4,[]);

At=A';

Bt=B';

data=horzcat(A',B');

The trace says that the data is for one day and the time stamp is in seconds. But the difference between the smallest time stamp and the largest is not equal to 86400(60*60*24).I am just not able to identify where I went wrong. Please help.

Answer 1

[dpb]

nt_32=fread(fid,'4*uint32',4);

From doc for fread --

    When SKIP is used, the PRECISION string may contain a positive
    integer repetition factor of the form 'N*' which prepends the source
    format of the PRECISION argument, like '40*uchar'.  Note that 40*uchar
    for the PRECISION alone is equivalent to '40*uchar=>double', not 
    '40*uchar=>uchar'.  ...

Think you need

nt_32=fread(fid,'4*uint32=>uint32',4);

and similarly for the uint8's as well.

I'd recommend

doc memmapfile

to you and look at mapping the structure to make the read a little cleaner altho your route should work if you get the type conversions correct.