Splitting an array into variable lengths depending on it's content

조회 수: 8(최근 30일)
I have an array containing S sections of data that I need to extract and create S new arrays each containing one of those sections. The start of each section has the string 'E0=' and is followed by the data I need (though this amount varies between section). i.e. if there are N elements, strf{2} is a cell
strf{2} = [E0= 5 614 82 97 E0= 91 44 7 E0= 54 774 624 6339 4 1...]
So far I have found each element of the array where 'E0=' is using this code:
dEpres = strcmp(strf{2}, 'E0=');
S = sum(dEpres);
dEelems = find(dEpres, S);
Such that dEelems = [1 6 10 ...].
What I want to do now is split this array into n arrays at the elements where 'E=0' is so I have:
array1 = [E0= 5 614 82 97] array2 = [E0= 91 44] array3 = [E0= 54 774 624 6339 4 1]
I have tried to use some sort of for loop to generate array(i) where i=1:S but haven't been successful.
Any help would be really appreciated!
Thanks, Matt

답변(1개)

Vishal Rane
Vishal Rane 2014년 3월 12일
If str = 'E0= 5 614 82 97 E0= 91 44 7 E0=54 774 624 6339 4 1...'
[matchstart,~,~,~,tokenstring,~,~] = regexp( str, 'E0=\s|E0=', 'split')
matchstart =
'' '5 614 82 97 ' '91 44 7 ' '54 774 624 6339 4 1...'
tokenstring =
'E0= ' 'E0= ' 'E0='
matchstart(1) = []
cellfun(@horzcat, tokenstring, matchstart, 'un', 0)
ans =
'E0= 5 614 82 97 ' 'E0= 91 44 7 ' 'E0=54 774 624 6339 4 1...'

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