slope to a circle

hi, how can i give slope two a circle using the code below,

if true
  % code
r=1
teta=-pi:0.01:pi
x=r*cos(teta);
y=r*sin(teta);
z=zeros(1,numel(x));
plot3(x,y,z);
hold on
end

[Image Analyst]

What do you mean by slope? Do you mean that you don't want the z values to all be the same so that it is parallel with the x-y plane? That you want the circle tilted/slanted so that it has a variety of z values?

Answer 1

[cr]

For you. Cheers.

function coordinates = arc(C,R,inplane,normal,t)
% ARC function generates coordinates to draw a circular arc in 3D
% arc(C,R,inplane,normal,t)
% R       - Radius
% C       - Centre
% inplane - A vector in plane of the circle
% normal  - A vector normal to the plane of the circle
% t       - vector of theta. E.g. for a full circle this is 0:0.01:2*pi

% By Chandrakanth R.Terupally

v = cross(normal,inplane);
coordinates = [C(1) + R*cos(t)*inplane(1) + R*sin(t)*v(1);
               C(2) + R*cos(t)*inplane(2) + R*sin(t)*v(2);
               C(3) + R*cos(t)*inplane(3) + R*sin(t)*v(3)];

end

Answer 2

[Image Analyst]

Try this:

fontSize = 20;  
r=1;
theta = linspace(-pi, pi, 90);
x = r * cos(theta);
y = r * sin(theta);
tiltFactor = 1.0;
z = tiltFactor  * x;
plot3(x,y,z, 'bo-', 'LineWidth', 2);
hold on
grid on
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);
zlabel('Z', 'FontSize', fontSize);
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);