I've used Matlab a long time (10+ years) but for the life of me I can't do something rather stupidly simple: get an object's name (not its class name but the name of a specific instance). For testing purposes, I just need a function to print out the name of a specific instance of an object. Surely there is a straightforward way to do this that I'm overlooking but it doesn't easily show up in any of the help retrievals I've tried. None of my fellow Matlab users here at work could give me any help. (I know I'm going to be red-faced when I learn (relearn?) the method.)

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Sean de Wolski
Sean de Wolski 2011년 7월 7일

0 개 추천

whos
?
x = whos;
idx = cellfun(@(x)strcmp(x,'double'),{x(:).class}); %change 'double' to your class
x(idx).name

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Christopher Ison
Christopher Ison 2011년 7월 7일
Thanks for the speedy reply! Yes, this seems to work pretty well at the command prompt. I will do some more testing inside functions to see how well it works there.
Sean de Wolski
Sean de Wolski 2011년 7월 8일
It works fine in functions, you may just have to wrap it with 'evalin' to go up a layer.
Lucas Schneeberger
Lucas Schneeberger 2020년 4월 1일
I did it and I think that does not work if you have several instances of the same class
CCC
CCC 2021년 5월 31일
I would like to do that with a method within the instance itself.
If you use evalin for example in 'base' you may overwrite x if exists (can be solved)
but then you get, as Lucas mentioned a list of the same class, you could add a unique property to each instance so that:
Looking for something more elegant!
function charname = getInstanceName(obj)
% Handle this variables as inputs, properties or whatever you want:
yourclass = obj.type; % Any comand that returns your instance's class.
workspaceoftheinstance = 'base';
propertyID = 'Reference'; % Any unique ID of your instance.
% Just a way to avoid using X, looking for a better one, or
% simply use the 'else'.
if ~evalin(workspaceoftheinstance,'exist(''x'')')
evalin(workspaceoftheinstance,'x = whos;');
x = evalin('base','x');
else
evalin(workspaceoftheinstance,...
'super_long_variable_name_nobody_would_use_for_this = whos;');
x = evalin(workspaceoftheinstance,...
'super_long_variable_name_nobody_would_use_for_this');
end
% Same as the Accepted Answer:
idx = cellfun(@(x)strcmp(x,yourclass),{x(:).class});
instances = x(idx);
if length(instances)>1
% We try to solve the list of instances of the same class with the
% unique .Reference property (same solution as Accepted Answer):
for i = 1:length(instances)
if evalin(workspaceoftheinstance,['strcmp(',instances(i).name,'.',propertyID,...
',''',obj.Reference,''')'])
charname = instances(i).name;
obj.varname = instances(i).name;
break
end
end
else
% There's only one.
charname = instances.name;
obj.varname = instances.name;
end
end
IF you're doing this for diagnostic purposes (to include the name of the input in a warning or error message) and not to try to reach into the calling workspace to modify the object and if you're able to handle the scenario where the input has no name use inputname.
x = 1:10;
showInputName(x)
The name of the input is 'x'.
showInputName(1:10)
The input has no name.
function showInputName(in)
s = inputname(1);
if isempty(s)
fprintf("The input has no name.\n")
else
fprintf("The name of the input is '%s'.\n", s)
end
end

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추가 답변 (2개)

Christopher Ison
Christopher Ison 2011년 7월 8일

2 개 추천

Well, I found the short answer and it's really, really stupid:
function namestr = getobjname(obj)
namestr = inputname(1);
So if I type this at the command line:
namestring = getobjname(myobject)
If "myobject" exists, it returns
>>namestring = myobject
which can now be printed in an output display. Very helpful, Mathworks.

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tom_brot
tom_brot 2015년 3월 24일
편집: tom_brot 2015년 3월 24일
This is a very neat solution. I do it like this now:
methods
function name = objName(self)
name = inputname(1);
end
end
In this way you get your objects Name by
yourobject.objName
The Problem is, this works perfectly from outside the object, but it doesn't works in another method.
methods
function displayname(obj)
display(obj.objName)
end
end
Then the output is just
obj
So the new Task is: Retrieve an object's name WITHIN A METHOD
any ideas?
Lucas Schneeberger
Lucas Schneeberger 2020년 4월 1일
편집: Lucas Schneeberger 2020년 4월 1일
Is there a way to get the name of the instance inside the class constructor ? I would like to assign a value to obj.name property during the object construction.
This would require the left part of the assignment as in
instance_name = Class(varargin)
to be already processed when constructing the object, I am not sure if it is the case ...
Steven Lord
Steven Lord 2020년 4월 1일
I would like to assign a value to obj.name property during the object construction.
See the "Initializing Objects in Constructor" section on this documentation page for several examples of how to do this. There's no need to know with what name the class constructor was called to store the output (or even if that output has a name: mycell{1} = myObjectConstructor; is a perfectly valid way to call an object constructor and store the resulting object in a cell in a cell array.)

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Paul O'Brien
Paul O'Brien 2018년 11월 13일

0 개 추천

In MatLab R2016b, if I have a variable "obj" referring to an object, you can get a list of methods by typing
obj.
and then pressing the tab key. One of the methods is called "string", and
obj.string
yields a string containing the name of the object.

댓글 수: 1

That assumes that the class author has chosen to overload the string method to behave that way. As an example of where this could fail is the table class:
>> t = array2table(magic(4));
>> class(t)
ans =
'table'
>> string(t)
Error using string
Conversion to string from table is not possible.
This is one case where string(t) and t.string behave differently, but neither gives the name of the variable.
>> t.string
Unrecognized variable name 'string'.

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2011년 7월 7일

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2021년 5월 31일

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