Hi,
I made a 2d matrix with two for loops:
for k = 1:32
for l = 1:32
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
P_old is here a 32 x 1 matrix and LODF is a 32 x 32 matrix which is already computed. How can I vectorize this code to avoid the for loops? Thanks in advance.

 채택된 답변

Matt J
Matt J 2013년 12월 10일

0 개 추천

P_new= bsxfun(@times, LODF, P_old.');
P_new= bsxfun(@plus, P_new,P_old);

댓글 수: 2

Jip
Jip 2013년 12월 10일
편집: Matt J 2013년 12월 10일
Although this code avoids the for loops, it is not faster, which is my purpose. Actually the code is much slower. Any other suggestions?
Matt J
Matt J 2013년 12월 10일
편집: Matt J 2013년 12월 10일
For 32x32 data, I wouldn't be surprised if the for-loop was the fastest approach. For larger sizes, however, the vectorized approach will start to show superior performance, e.g.,
N=3200;
LODF=rand(N); P_old=rand(N,1);
tic;
P_new=zeros(size(LODF));
for k = 1:N
for l = 1:N
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
toc;
%Elapsed time is 0.102201 seconds.
tic;
P_new= bsxfun(@times, LODF, P_old.');
P_new= bsxfun(@plus, P_new,P_old);
toc
%Elapsed time is 0.043591 seconds.
If you're not happy with the speed of your code, you should show us the slow part in its entirety. The small part you've shown is pretty fast, in and of itself.

댓글을 달려면 로그인하십시오.

추가 답변 (2개)

Jos (10584)
Jos (10584) 2013년 12월 10일

0 개 추천

for loops are pretty fast when you use pre-allocation
P_new = zeros(32,32) ;
for k = 1:32
for l = 1:32
P_new(l,k) = P_old(l) + (LODF(l,k) * P_old(k));
end
end
Jip
Jip 2013년 12월 10일

0 개 추천

Yes I know, I already did that.

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

Jip
2013년 12월 10일

편집:

2013년 12월 10일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by