How to substitute multiple values in symbolic matrix?
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Hi, How to substitute multiple values in symbolic matrix? With function subs, we can substitute only single value in expression. Writing nested subs(subs(...)) can work but it becomes tedious. Here is sample code:
syms x y z w
N=[ 1y+y+z,x/2 - y/3 + z/3, x*y, x+z];
Is there any way to substitute values to w,x,y,z in single line? I guess then I have to define variables like x(1), x(2) etc. and have to use for loop to change values. Is this approach correct or is there any better way?
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Andrei Bobrov
2013년 11월 29일
syms x y z w
N=[ w+y+z,x/2 - y/3 + z/3, x*y, x+z]
X = sym(['[',sprintf('X(%d) ',1:4),']'])
out = subs(N,[x, y, z, w],X)
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Deepayan Bhadra
2016년 12월 5일
Hi,
I wanted some explanation on how the above code works. Say my N is a 6x6 matrix with 5 symbolic variables and I want to evaluate N at one go, for 5 different values of the variables. How do I modify the above answer for that? Thank you.
Karan Gill
2016년 12월 8일
That answer is wrong. Please do not use string input to sym. Instead:
>> syms x y z w
N=[ 1*y+y+z,x/2 - y/3 + z/3, x*y, x+z];
vars = [w x y z];
newVars = sym('x%d',[1 4]);
subs(N,vars,newVars)
ans =
[ 2*x3 + x4, x2/2 - x3/3 + x4/3, x2*x3, x2 + x4]
Much easier to read and understand. Look up the doc for sym to understand the command I used: https://www.mathworks.com/help/symbolic/sym.html
추가 답변 (1개)
Youssef El Seblani
2018년 3월 31일
편집: Walter Roberson
2018년 3월 31일
clc
clear
syms x y z w
N=[ w+y+z,x/2 - y/3 + z/3, x*y, x+z]
A=sym('X',[1,4])
N(A) = subs(N,[x, y, z, w],A)
for example
N(1,2,3,4)
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Walter Roberson
2018년 3월 31일
This will not work if I recall correctly. You cannot use a vector of symbolic variables after a variable name in order to define a function of multiple parameters. Instead each variable must be a separate parameter.
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