This is what I have:
xA=[0 4 2 1]; wA=struct('name',{'person1' 'person2' 'person3' 'person4'},'num',num2cell(xA)); peopleA={wA.name}; numA=[wA.num]; [idxA,idxA]=max(numA); primeroA=peopleA{idxA} numAA=numA(numA~=max(numA)); [idxxA,idxxA]=max(numAA); segundoA=peopleA{idxxA}
I want to remove the maximum of the word, that is, the word contained in primeroA, in order to be able to calculate the second maximum without the words being rearrenged or altered.

 채택된 답변

Andrei Bobrov
Andrei Bobrov 2013년 11월 4일

0 개 추천

xA=[0 4 2 1];
name={'person1' 'person2' 'person3' 'person4'};
[a,b] = unique(xA);
out = name(b(end-1));

추가 답변 (1개)

Azzi Abdelmalek
Azzi Abdelmalek 2013년 11월 4일
편집: Azzi Abdelmalek 2013년 11월 4일

0 개 추천

xA=[0 4 2 1];
wA=struct('name',{'person1' 'person2' 'person3' 'person4'},'num',num2cell(xA));
peopleA={wA.name};
numA=[wA.num];
[idxA,idxA]=sort(numA,'descend');
primeroA=peopleA{idxA(1)}
segundoA=peopleA{idxA(2)}
terceroA=peopleA{idxA(3)}

댓글 수: 1

Thank you soo much!! You are a genius! I'm sorry..I accepted the wrong answer and I don't know how to unaccept it. But thank you very much!

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