I have the following `for-loop` part of a function:
for i=1:5
for j=1:2
m=x(i)-c(j);
end
end
As a call to the function which includes the code above, I pass `two` values for `c`. Say the values passed are `(3,5)` for `c1` and `c2` respectively.
As you see in the `for-loop` above, I will have a two values for `c`, nanely, `c(1)` and `c(2)`.
For the `3` and `5` values I have above, how can I assign them to `c(1)` and `c(2)` respectively?
When I did the following for instance:
c(1)=center1;
c(2)=center2;
where `center1` and `center2` represent the passed value to the function, I got the following error:
In an assignment A(I) = B, the number of elements in B and I must be
the same.
Error in functionName (line 32)
c(1)=center1;
Thanks.

댓글 수: 2

Azzi Abdelmalek
Azzi Abdelmalek 2013년 10월 30일
What is the value of center1?
James Tursa
James Tursa 2013년 10월 30일
What are the dimensions of center1 and center2?

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2013년 10월 30일

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2013년 10월 30일

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