Why do I see a cast to signed integer on my unsigned array index?
조회 수: 6 (최근 30일)
이전 댓글 표시
We explain here why even if the index of an array is unsigned, Polyspace says that there is conversion to signed integer
채택된 답변
MathWorks Support Team
2012년 7월 17일
Example of implicit cast from unsigned to signed:
unsigned int r;
int tab[3] = {1,2,3};
void f(void) {
int x;
x = tab[r];
// check details on 'r' says :
// global variable 'r' (unsigned int 32): full-range [0 .. 2^32 -1]
// conversion from unsigned int 32 to int 32
}
The C Standard says that array indexes are (signed) integers. The reason behind that is that pointers and arrays are close in C.
For example, tab[index] is strictly equivalent to *(tab + index).
You can use pointer arithmetic with negative values, hence an array index can be negative.
Exemple of valid array access with a negative index:
void f(void) {
int x;
int *p;
int tab[3] = {1,2,3};
p = &tab[2]; // points to the 3rd element
x = p[-1]; // x is assigned to the second element, '2'
}
댓글 수: 0
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Command-Line Only Options에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!