Notae

Last seen: 17일 전 | 2025년부터 활동

Followers: 0 Following: 0

통계

Feeds

질문

Different results of the same caculation by loop code and by array code
r=1e9; A=0; for i=1:r A=A+floor(sqrt(r^2-i^2)); end A --------------- i=[1:r]; A=sum(floor(sqrt(r^2-i.^2))) ------...

12개월 전 | 답변 수: 1 | 0

1

답변