photo

merlin toche


Last seen: 대략 1개월 전 2022년부터 활동

Followers: 0   Following: 0

통계학

  • Thankful Level 1
  • First Answer
  • Explorer

배지 보기

Feeds

보기 기준

질문


How calculate the class membership of each training sample using Fuzzy-kNN
I want to use the FKNN to classify my data, but I can't calculate the class of membership of each training sample. I tried to wr...

1년 초과 전 | 답변 수: 0 | 0

0

답변

질문


how to implement fuzzy-KNN code to fault detection
Hi everybody! please, I come to you once again to seek clarification. indeed, I want to use the fuzzy-KNN algorithm to detect ...

1년 초과 전 | 답변 수: 0 | 0

0

답변

질문


fuzzy-kNN algorithme for fault detection
Hello everyone, while thanking chaucn, I come back with a concern about the fuzzy-kNN algorithm indeed, I want to detect fault...

1년 초과 전 | 답변 수: 0 | 0

0

답변

질문


how to determining threshold distance using knn
Hello everyone please i still need you I want to detect defects and classify them using the kNN rule. however with your help I...

1년 초과 전 | 답변 수: 0 | 0

0

답변

답변 있음
how to replace a dataset with another one in matlab
please how to do appear fault detect and threshold in knn graph. i want to know it please

1년 초과 전 | 0

질문


how to implement fuzzy logic code without using fuzzy Toolbox
Hello. I need to implement a fuzzy logic code in matlab without using toolbox, i have two input power and voltage and i shoul...

1년 초과 전 | 답변 수: 1 | 1

1

답변

질문


how to evaluate my result knn code using confusion matrix
sir, although I can't replace the old data, I have tried several times to use the App toolbox (ClassificactionLearner) to evalua...

1년 초과 전 | 답변 수: 1 | 0

1

답변

질문


how to replace a dataset with another one in matlab
hello everyone please, I had imported my dataset to run my code, but since then I want to replace this dataset. indeed, when I ...

1년 초과 전 | 답변 수: 2 | 0

2

답변

답변 있음
Knn classification on a dataset
thank you sir for all you do for me. well explained and well understood. excuse me for continuing to bother you, please, I'm s...

1년 초과 전 | 0