The aim is to find all the zeros of a function within an interval.
output = find_zeros(@sin,0,2*pi) will return :
output = [0.0000 3.1416 6.2832]
since the sinus function between [0 2pi] is zero for [0 pi 2pi]
I think test case 2 might be incorrect.
I disagree slightly with the expected solution to test 2.
Test 2 cos between [0 2pi]
[-pi/2 pi/2 3*pi/2]
I do not believe that -pi/2 is in the interval [0 2*pi].
If -pi/2 is desired then the answer to sin [0 2*pi] should be [-2*pi -pi 0 pi 2*pi]
Correction of assert function.
One of the ")" is in the wrong place.
assert(all(abs(find_zeros(@sin,0,2*pi) -[0 pi 2*pi]<1e-9))
Yeah, the test set is wrong...
Find the peak 3n+1 sequence value
Reverse the vector
Back to basics 25 - Valid variable names
Converting Decimal to Binary
Stuff the Board
Join Strings with Multiple Different Delimiters
Return unique values without sorting
Number of bytes required to store a sparse matrix
Set the array elements whose value is 13 to 0
Sophie Germain prime
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