Problem 672. Longest run of consecutive numbers

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Solution 4536613

Submitted on 4 Jan 2021 by Sarker Ashraful Islam

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Leading solution size is 32.

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1 Comment

1 Comment

Hello Say on 6 Oct 2021

hello, i have problem understanding the code,
in:
for c=1:l
for r=c:l
if a(c)==a(r)
freq(c)=freq(c)+1
else
break
end
end
end
why didn't the c=1,r=5 satisfy the "a(c)==a(r)",in a(c)==a(r)
thanks a lot

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