Problem 62. Elapsed Time

Created by Cody Team

Solve Later

Given two date strings d1 and d2 of the form yyyy/mm/dd HH:MM:SS (assume hours HH is in 24 hour mode), determine how much time, in decimal hours, separates them. Assume d2 is always later than d1.

Example:

 Input d1 = '2010/12/14 12:00:00'
 Input d2 = '2010/12/14 13:06:36'
 Output elapsed is 1.11

Solve

Solution Stats

Last solution submitted on Aug 19, 2019

Last 200 Solutions

Problem Comments

9 Comments

9 Comments

Show 6 older comments

Bobby Cheng on 27 Jan 2012

The testsuite input does not following the input format string.

Chew Baca on 13 Mar 2013

Having a hard time with the test suite regarding the number of hours in one year. I think it should be 8 765.81277h/y

Matthew Kishe on 15 Aug 2013

The test suite doesnt follow. it should be double digit days and month, not single digits according to his descrption

Hassan Javaid on 5 Sep 2013

having problems with the test suite especially test no 3

Gareth Lee on 10 Nov 2014

having problems with test no 3 of the test suite,why?

Riyasat on 5 Feb 2015

It's a fun problem

huashou on 11 Apr 2017

the test suits are all passed , but the mathworks net tells its wrong.
and the size is '-1'.
i use the datenum function.

Chen Qian on 11 Jun 2019

I use format bank to get 2 decimal output, anyone has a better idea?

Sanzhar Askaruly on 6 Jul 2019

using existing functions makes this trick easy

Solution Comments

Solution 1893405

1 Comment

1 Comment

liu xinyang on 7 Aug 2019 at 3:22

This test program is wrong.To judge a leap year, you need to calculate if the following condition is satisfied mod(year,4)==0 & mod(year,100)~=0 & mod(year,400)==0. However, this team only count those years that mod(year,4)==0

Solution 1202027