This problem is inspired by Dyuman Joshi's problem 58329. Given a row vector x and a natural number n, remove all runs of at least n consecutive NaNs from x, leaving all shorter runs as well as all non-NaN elements intact.
For instance, given
x = [1 NaN 2 3 NaN NaN 4 5 6 NaN NaN NaN 7 8 9 10 NaN NaN NaN NaN]
the results would be as follows:
>> removenans1n(x, 1)
ans =
1 2 3 4 5 6 7 8 9 10
>> removenans1n(x, 2)
ans =
1 NaN 2 3 4 5 6 7 8 9 10
>> removenans1n(x, 3)
ans =
1 NaN 2 3 NaN NaN 4 5 6 7 8 9 10
>> removenans1n(x, 4)
ans =
1 NaN 2 3 NaN NaN 4 5 6 NaN NaN NaN 7 8 9 10
>> removenans1n(x, 5)
ans =
1 NaN 2 3 NaN NaN 4 5 6 NaN NaN NaN 7 8 9 10 NaN NaN NaN NaN
with no changes in output for even higher n (since x only contains runs of NaNs up to length four).
To make this challenging, provide a vectorized solution: no loops, no arrayfun (in fact, no fun at all, though you're still allowed to have fun), and no recursion. Regular expressions are also outlawed (I don't think that this is a problem that is naturally solved using regular expressions, so I don't feel too bad about doing so).
Solution Stats
Solution Comments
Show comments
Loading...
Problem Recent Solvers7
Suggested Problems
-
Make the vector [1 2 3 4 5 6 7 8 9 10]
53583 Solvers
-
2019 Solvers
-
Convert Roman to Arabic Numerals
125 Solvers
-
Calculate the probability that at least two people in a group share the same birthday.
106 Solvers
-
Free Fall analytical solution (Chapra 2012 textbook Example 1.1)
27 Solvers
More from this Author20
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!