Given two numbers, m and n, find a matrix m x n where each element value is twice the value of the previous element. Starting from the position (1,1) with value equal to 1, until the position (m,n), following the direction from left to right in each row.
For example, for m=2 and n=3, one should get:
y = [1 2 4; 8 16 32].
163 Solvers
Sum of odd numbers in a matrix
208 Solvers
348 Solvers
138 Solvers
16 Solvers
Solution 1717118
Test 4 is wrong; y_correct should be [1; 2; 4]
I´m afraid all tests are correct. But thanks anyway!