Problem 43590. Solve t^(ax^2+bx+c)=s

Created by Andriy Kavetsky

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Solve t^(a*x^2+b*x+c)=s. Return x vector as result.

Example a=1, b=2, c=1, t=3, s=15. Result x(1)= 0.5700 x(2)=-2.5700

Hint: if we need to solve a*x^2+b*x+c=0 then result will be

x(1)=(-b+sqrt(b^2-4*a*c))/(2*a);

x(2)=(-b-sqrt(b^2-4*a*c))/(2*a);

Solve

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Last Solution submitted on Jun 16, 2020

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2 Comments

David Verrelli on 3 Jul 2018

The Test Suite only accepts one ordering of the two x values, but the ordering is not explained. See e.g.  Solution 1574317. Either the Test Suite or the Problem Statement needs to be amended. Also, it is recommended that at least four test cases be provided, though more are often necessary to prevent hard-coded workarounds. —DIV

David Verrelli on 3 Jul 2018

Sorry, I suppose the "hint" does suggest that descending order is wanted. However it would still have been beneficial to state it explicitly. —DIV

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Problem 43590. Solve t^(ax^2+bx+c)=s

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Problem 43590. Solve t^(a*x^2+b*x+c)=s

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Problem 43590. Solve t^(ax^2+bx+c)=s