Given n, calculate the number 2^n (where n>=0) and iterate until the sum of the digits is a single-digit number.
Input n = 7
Output sum = 2
because 2^7 = 128, and 1+2+8=11 and 1+1=2.
I clarified the problem statement and fixed one test case to make the problem solvable as originally intended.
Anyone else running into an issue with 2^111? I'm getting 2^111 = 2596148429267413814265248164610048, which sums to 143, which sums to 8. The test suite says 9.
The last test is not correct. Could you check it ?
Yes, this is a sequence (1 2 4 8 7 5 1 2 4 8 7 5 ...)
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