given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Is my wife right?
Find the hypotenuse
07 - Common functions and indexing 4
prime test 2
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office